Liter Bubble
If 0.050 moles of gaseous HCl is bubbled in 1.0 liter of a solution that is 0.15 M in NH3 and 0.10 M in NH4Cl,
what will be the pH of the resulting solution?
use henderson-hasselbach's equation:
pH=pKa+log([base]/[acid]) or
pH=pKa+log(n base/ n acid)
n acid (NH4+) = M*V = 0.10 mol
n base (NH3)= M*V = 0.15 mol
after HCl addition (0.050 mol)
n acid (NH4+) = 0.10 + 0.050 = 0.015 mol
n base (NH3)= 0.15 - 0.050 = 0.010 mol
pH = pKa+ log(0.010/0.015) = pKa - 0.18
now you only need pKa to solve
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Dry Ice Boo Bubbles
How do you convert cm to litres?
I am doing a grade 5 science experiment....
they are blowing bubbles on a table with dish detergent... how would they convert the diameter of the popped bubble into litres?
Assuming the bubbles are relatively spherical (which generally they are), the volume of the bubble would be:
Volume = 4π(r^3)/3
Where r is the radius.
Since you're measuring the diameter, you just have to change r to d/2. Since you're also wanting to go from cm to liters, you have to multiply the whole thing by 1000 (a liter is 1000 cubic centimeters). So if you make those changes, you'd get:
Volume = 500π(d^3)/3
Where the diameter, d, is measured in centimeters and the volume will be in liters.
EDIT: Sorry! I got the conversion from cm^3 to liters backwards. You should divide by 1000, not multiply, so the proper expression for the volume is:
Volume (in liters) = π(d^3)/6000, (d is in cm)
