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Square Straight Segment
COMPOSITE FIGURES!!!!!!!!?
What is the area of the composite figure shown?
A two-dimensional figure is shown that resembles a square with a triangular section removed from the bottom. The left and right side are parallel and meet the top side at ninety degree angles. All three sides measure fifty centimeters. A fourth line segment begins at the bottom of the left side and ends at the center point of the figure. A fifth line begins at the bottom of the right side and ends at the center point of the figure, meeting the fourth line segment. A dotted line extends from the point where the fourth and fifth segments meet straight downward creating a ninety degree angle with a second dotted line the extends from the bottom of the left side of the figure. The first dotted line is labeled twenty-five centimeters.
you need to post the figure
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Speed Square Segment 3: Submarines, Steamboat, Stars
MATH is a parallelogram with diagonals intersecting at O. what shape is it depending on the description?
we have a shape kinda like a rhombus with letters m (top left) a (top right) t (right bottom) h (bottom left) and it has a line straight threw the middle with o at the place they intersect.
the description is (segment) mo congruent to (segment) ot, (segment) ao congruent to (segment) oh. what type of shape is it? rhombus, square, rectangle, im not sure if u can put parallelogram since it was in the question?
It is a parallelogram. Parallelograms have the property that opposite sides are equal. You have oh congruent to oa, ox congruent to om, and then angles moh and aox equal because they are vertical angles, so by SAS you can conclude triangles moh and oax are congruent, so sides mh and at are congruent, similarly angles moa and toh are equal because they are vertical angles, so by SAS triangles moa and toh are congruent, and side ma is congurent to side ht. This need not be a rhombus, rectangle, or square though if that is all the information you have because parallelogram's diagonals are bisected by each other, which is also true of all the other shapes, but without more restrictions, a regular parallelogram is sufficient.
